find all inflection points for x^3 + 30x^2

find the x and y coordinates of all inflection points. x^3 + 30x^2
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f(x)=x³+30x², f'(x)=3x²+60x=0 at an extremum. So 3x(x+20)=0, that is, x=0 and x=-20.

f(0)=0 and f(-20)=-8000+12000=4000.

f''(x)=6x+60=6(x+10), f''(0)>0 (minimum at (0,0)) and f''(-20)<0 (maximum at (-20,4000)).

by Top Rated User (1.1m points)

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