slove x^2=(x-2)^2+4^2

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1 Answer

x2=(x-2)2+42, then:

42=x2-(x-2)2=(x-x+2)(x+x-2)=2(2x-2),

16=4x-4, 4=x-1, x=5.

So the Pythagorean triangle has side lengths 3, 4, 5.

by Top Rated User (1.1m points)

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