x is 5 less than y. Twice the second number is 2 less than 5 times the first. Find the two numbers.

can you help me? I dont know how to do this math problem
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Assume y is the second number and x is the first: 2y=5x-2; x=y-5, so y=x+5 (add 5 to both sides) and 2y=2x+10 (doubling both sides); substitute for 2y: 2x+10=5x-2; 12=3x (subtract 2x from both sides, then add 2 to each side); x=4 (divide through by 3);  y=9 because y=4+5, substituting x=4.

 

 

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