Solving differential equations
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1 Answer

xdy/dx=1-y^2

cross-multiply to get,

1/(1 - y^2) dy = 1/x dx

integrate both sides,

int 1/(1 - y^2) dy = int 1/x dx

atanh(y) = ln(Ax)

y = tanh(ln(Ax))

by Level 11 User (81.5k points)

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