1) -2x + y = 0
2) -3x - 2y = -35
We can eliminate y; multiply equation 1 by 2.
2 * (-2x + y) = 0 * 2
3) -4x + 2y = 0
Add equation 2 to equation 3.
-4x + 2y = 0
+(-3x - 2y = -35)
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-7x = -35
-7x = -35
-7x/-7 = -35/-7
x = 5
With that, we can use equation 1 to solve for y.
-2x + y = 0
-2(5) + y = 0
-10 + y = 0
-10 + y + 10 = 0 + 10
y = 10
Use equation 2 to check the answers.
-3x - 2y = -35
-3(5) - 2(10) = -35
-15 - 20 = -35
-35 = -35
Answer: x = 5, y = 10
Problem statement: what is the answer to ... -2x+y=0 -3x-2y=-35
it has to do with "solving systems of equations:elimination method