Question

Graph the equation with a diameter that has endpoints at (-2,-2) and (4,2). label the center and at least four point on the circle. write the equation of the cirlce

Answer 1

Centre lies at the midpoint of the diameter which is ½(4-2,2-2)=(1,0), so the equation of the circle will look like: (x-1)²+y²=r², where r is the radius, and:

r²=(-2-1)²+(-2-0)²=3²+2²=13, (x-1)²+y²=13 is the equation of the circle.

A(-2,-2) and B(4,2) are the given points (AB is the diameter). O is the centre at (1,0).

C(1+√13,0) and D(1-√13,0) are the x-intercepts.

E(-2,2) and F(3,-3) are two more points in the circle.