how to solve x^5-8^3-9x=o by using the theorem of algebra

i need to solve x^5-8^3-9x=0 how many zeros
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I guess this is supposed to read x^5-8x^3-9x=0; x(x^4-8x^2-9)=0; x(x^2-9)(x+1)=0; x(x-3)(x+3)(x+1)=0.

Zeroes are: 0, 3, -3, -1.
by Top Rated User (1.1m points)

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