the number of motor vehicle death increased by 13.75 times from 1912 to 2003.

There were 39525 more deaths in 2003 than 1912. find the number of deaths in each of the two years.

how do i set up the equation? I know 1912=x and 2003= 39525+x

but where does the 13.75 come in and the number of years?
in Algebra 2 Answers by

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1 Answer

using linear equations what is the equation?
the number of motor vehicle death increased by 13.75 times from 1912 to 2003.
There were 39525 more deaths in 2003 than 1912. find the number of deaths in each of the two years.
how do i set up the equation? I know 1912=x and 2003= 39525+x
but where does the 13.75 come in and the number of years?

You made a good start by assigning values for the two years given.
The 13.75 come in when the problem states that the vehicle deaths
in 2003 were 13.75 times as numerous, i.e., 13.75 * x
That gives us an equation we can solve for x.

13.75x = x + 39525
13.75x - x = x + 39525 - x
12.75x = 39525
x = 39525 / 12.75
x = 3100 vehicle deaths in 1912
x + 39525 = 3100 + 39525 = 42625 vehicle deaths in 2003
Also, 13.75 * 3100 = 42625
by Level 11 User (78.4k points)

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