if f(x-2) = -[(x+1)(x+1)] then f(t-3)=
Let us simplify things by finding the expression for f(u), where u = x - 2, or x = u + 2
i.e. f(u) = -[(u + 2 + 1)(u + 2 + 1)]
f(u) = -[(u + 3)(u + 3)]
f(u) = -(u + 3)^2
Now find f(t - 3) by using the substitution u = t - 3 in the expression for f(u)
f(t - 3) = -(t - 3 + 3)^2
f(t - 3) = -t^2