if x^1/p=y^1/q=z^1/r and xyz=1 then the value of p+q+r is

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Let all these be equal to variable u, then x=u^p, y=u^q, z=u^r, and xyz=u^(p+q+r)=1.

Taking logs: (p+q+r)ln(u)=0. Since in general u≠1, p+q+r=0. Any base for the logs will give the same answer.

 

by Top Rated User (1.1m points)

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