if f(x)=ax^2+6x+33a has Inflection point in x=9 whew y=0 in thids parabola?

a=an unkown number

can we use evrey value that we know to slove?

can be two points on the parabola?
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1 Answer

first slove -b/2a=9

b=6 and a=a

9=6/2a-

-6=18a

a=-6/18

a=-1/3

 

f(x)=-1/3x^2+6x-11=0

►

6*6=36

4(-11)(-1/3)=14 2/3

►=21 1/3

21 1/3

x≈2

x≈16

by

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