1+secx/tanx+sinx

Solve this problem using trig identities.

1+secx/tanx+sinx
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1 Answer

(1+sec(x))/(tan(x)+sin(x)).

Multiply top and bottom by cos(x):

(cos(x)+1)/(sin(x)+sin(x)cos(x))=

(cos(x)+1)/(sin(x)(1+cos(x))=1/sin(x)=cosec(x).

by Top Rated User (1.1m points)

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