2x^2 + 3x - 2

Find the Maximum and Minimum Value for this quadratic

Find the range and domain for this quadratic

Find the end behavior for this quadratic

Find the interval of increase for this quadratic

FInd the interval of decrease for this quadratic

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1 Answer

y
= 2x^2 + 3x - 2
= (2x^2 + 3x) - 2
= 2(x^2 + (3/2)x) - 2
= 2(x + (3/4))^2 - 9/8 - 2
= 2(x + (3/4))^2 - 25/8

Notice that 2(x + (3/4))^2 >= 0 for all real values of x.
Thus, maximum value is infinite and minimum value is -25/8.

domain is all real numbers, whereas range is [-25/8 , infinity)

As x tends to infinity, y also tends to infinity.
As x tends to negative infinity, y tends to infinity.

The interval of increase will be (-25/8 , infinity)
The interval of decrease will be (-infinity , -25/8)
How do we know this?
The answer is by looking at the end behaviour and the range.
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