A park has an area of 64sq meters and a perimeter of 40 meters. Find the length and width of the park.
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1 Answer

Several problems heer...first=yu shood tell us the shape at the "thang"

sins yu sae leng & wide, me assume thang=rektangel

then yu sae area=64m...me suppose m is meters, & thats rong

it wood hafta be m^2

rim-leng=40, so half-rim=20=leng+wide

area=leng*wide=wide*(20-wide)=64

-wide^2 +20wide -64=0   or wide^2 -20 +64=0

wide=4 or 16...leng=16 & area=4*16=64
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