Please show me how to solve 1/3=9^2x-5

i need to solve this question for an algebra 2 review, but I'm not sure what chapter it is in.
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1 Answer

me assume thats spozed tu be

9^2x -5=1/3

or 9^2x=5& 1/3 =5.33333333333...

log(9^2x)=2x*log(9) =log(5.3333333)

so 2x=log(5.333333) / log(9)

=0.726998727 / 0.954242509

=0.761859506
by

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