Solving probabilities

Question

A bag contains 6 red marbles, 3 blue marbles and 7 green marbles. If three marbles are drawn out of the bag, what is the probability, to the nearest 10th of a percent, that all three marbles drawn will be green?

Solving Probabilities.

Answer 1

There are 16 marbles in the bag, but only 7 are green, so the chances of drawing a green are 7/16. That leaves 15 marbles, 6 of which are green, so the chances of the second marble being green are 6/15. And the chances for a third green marble are 5/14. The combined chance is therefore 7/16*6/15*5/14=1/16=0.0625 or 6.25%. To the nearest tenth of a percent this is 6.3%.