Writing the equation of a parabola?

Question

How would you write the equation of a parabola given the following:

 

The parabola has roots of 2 and 4 and opens up. It is congruent to y=3x^2. Write the equation of the parabola in y=a(x-p)^2+q form.

Answer 1

0 = 3(2 - p)^2 + q
0 = 3(4 - p)^2 + q
p = 3, q = -3

Answer: y = 3(x - 3)^2 - 3

Answer 2

how do you write the difference of 17 and 4 as an algebraic expression

Answer 3

z^4=(1+i) find the roots of this equation

Answer 4

Y=10x + 20