solve 4^x-32^(x-2)=8^2x

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1 Answer

Do you mean: 4x-32x-2=82x?

If so, we can see that 4=22 and 8=23, so:

22(x-3)2x-2=26x,

22x-6+x-2=26x, 23x-8=26x,

3x-8=6x, 3x=-8, x=-8/3.

by Top Rated User (1.1m points)

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