[(x^2y^-2)^-1]^-1

With solution pls. Thanks a lot! (this is why I write for a living. I hate Maaaath)
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1 Answer

[(x^2 * y^-2)^-1]^-1...

the outer "-1" kansel eech other...x^-1=1/x, then (1/x)^-1=x

so yu hav x^2 * y^-2...thats x^2 / y^2

or (x/y)^2
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