substitute x^2 for x and integrate from 0 to 1
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1 Answer

Given  int sin^2x

from ....cos2x=cos^2x-sin^2x

cos2x=[1-sin^2x]-sin^2x

=1-2sin^2x

sin^2x=1/2[1-cos2x]

int sin^2x=int 1/2[1-cos2x]dx

1/2int1 dx-1/2int cos2x dx

x/2-[sinx]/2

[x-sinx]/2

int sin^2x=[x-sinx]/2

 


 

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