Locate relative maxima and minima f(x)=-3/4x^4 +1/3x^3 +5x^2 +3

Supposed to use the first derivative test.Can you please show me the steps. Thanks!
in Calculus Answers by Level 1 User (740 points)

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1 Answer

df/dx=-3x^3+x^2+10x=0 at an extremum. This factorises: -x(3x^2-x-10)=0=-x(3x+5)(x-2). So the extrema are at x=0 (min), 2 (max) and -5/3 (max). (To find out the type of extrema we need to take the next derivative, but this has not been requested.)

by Top Rated User (1.1m points)

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