There are 4 jacks and 4 threes in a standard pack. Let's suppose we pick the order 33JJJ, then the probability of this order is 4/52*3/51*4/50*3/49*2/48=288/311,875,200. If we pick an alternative order, say, J3J3J, then the probability is 4/52*4/51*3/50*3/49*2/48, the same number. There are 10 arrangements of 3 jacks and 2 threes, but each different arrangement produces the same set of probabilities: (4^2*3^2*2)/(52*51*50*49*48). So there are 10 of these making the probability of 3 jacks and 2 threes in any order 2,880/311,875,200=1/108290=9.2345*10^-6 or 0.00092345%. The possible arrangements of 3 jacks and 2 threes are:
33JJJ, 3J3JJ, 3JJ3J, 3JJJ3, J33JJ, J3J3J, J3JJ3, JJ3J3, JJJ33, JJ33J