solve :2x^2-12x=0

Question

Solve the equation

Answer 1

x=6; x=0

Answer 2

2x^2-12x=0, factor x in 2x(x-6)=0, to have two possible roots of the equation I.e. x=0, +6. By plugging in the 6 as a possible root ignoring zero (0) we find that 2.6^2-12.6=0, then 2.36-12.6=0, 72-72=0 proving x as a root is correct and the other root has the same effect.

Answer 3

To solve by completing the square, first divide through by 2:

x²-6x=0, now complete the square:

x²-6x+9=9,

(x-3)²=9=3².

Taking the square root of each side:

x-3=±3, so x=3-3=0 or x=3+3=6. That is, x=0 or 6.

This is the same result as factoring 2x(x-6)=0

But the question required completing the square and not using a different method.