Solve the right triangle for which angle= 52.3° and c = 48.5.

Hi! please help me solve this. thanks
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rite triangel with 1 side=48.5 & 1 angel=52.3 deg... big quesshun: that side kros from that angel?????... yuno 1 angel=90 deg, so other angel=(90-52.3)=37.7 deg... yuze law av sines tu get all sines...(a/sine(angel a))=konstant... =(side b)/ sine(angel b)=(side c) / angel c... sine(52.3 deg)=0.791223533, so 48.5 /0.791223533=61.29746902=konst... so side kros from 90 deg...=61.29746.../sine(90 deg)... side=61.29746/1=61.29746
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