what will be the value of j=--k+2k+(l=k,l++)if k is 20 initially?

Question

value of k is 20.

Answer 1

??????????? "initially" ??????????? yu meen "at first" ???????... ?????? wot cha meen "--" ?????? zat spozed tu be "+" ???????... ?????? wot cha meen "l=l++ ?????? yu add 2 tu l ??????? the werd be EVALUATE thang at k=20... me thank that garbage b j=k+2k +k+2 at k=20=4k+2=80+2=82

Answer 2

The answer to this equation is 77.

Answer 3

J=--k+2k+(l=k,l++) k=20 ....given This implies, --k=19 and 2k=38 Also l=k=10...and l++=19 (since, post decrement operator) When we substitute all these values in the equation what we get is, J=19+38+19 J=76.

Answer 4

The value of j=20