find the value of b if root2+ root3/3 root2- 2root3=2- b root6

find the value of b if root2+ root3/3 root2- 2root3=2- b root6
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1 Answer

(√2+√3)/(3√2-2√3)=2-b√6,

(√2+√3)(3√2+2√3)/(18-12)=2-b√6.

Let x=√2, y=√3: (x+y)(3x+2y)=3x2+5xy+2y2=6+5√6+6=12+5√6. This substitution clarifies the multiplication using irrationals.

(12+5√6)/6=2-b√6,

2+5√6/6=2-b√6,

5√6/6=-b√6,

b=-⅚.

by Top Rated User (1.1m points)

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