Find all real zeros of the function g(x)=x^3-x^2-x+1

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1 Answer

x^3 - x^2  - x + 1 =x^2(x - 1 ) - 1 *( x - 1) =

 ( x - 1 )( x^2 - 1 )=( x - 1)( x - 1)( x + 1) = 0

x - 1 = 0 or x + 1 = 0

x = 1 or x = - 1

by Level 8 User (36.8k points)

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