0+50x1-60-60x0+10=
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27 Answers

My answer is -60 after doing the calculations
by
I got 0. After multiplying 0+50-60-0+10. Then add 50 - 60 +10. Equals 0
by
by my calculations the answer is 0
by
answer is 0.

who has asked for this qs?
by Level 1 User (700 points)
(-20) after calculations i got minus twenty
by
The answer is 10

0+50x1 =50-60= -10 -60= -70 x 0 = 0+10 =  10
by
0+50  = 50

50x1   = 50

50-60 = -10

-10-60=-70

-70x0  = 0

0+10 = 10

Answer is 10
by
20 remember, please exuse my dear aunt sally.  and a double negative makes a positve
by
Answer is -20

Order of operations: parentheses (none), exponents (none), multiply, divide (none), add, subtract

0+50x1-60-60x0+10

0+(50x1)-60-(60x0)+10

(0+50)-60-(0+10)

50-60-10

-20
by
the answer is  0
by

0+50 X1-60-60 X 0+10  = ????

=  50 X 1-120 X 10

=  50 (-119) X10

=  -5950  X 10

=  - 59500  

Please comment if you find it right or cross verify with some mathematician

thank you 

by
The answer is 0. Multiply, add, then subtract
by
0+50x1= 50

50-60=-10

60x0=0

-10+10=0

Answer is 0
by
0+50*1-60-60*0+10

0 +(50*1) -60- (60*0)+10

0+50-60-0+10=

0+(-10)-0+10=

-10+10= 0
by
PEMDAS

(multiply)

0+(50*1)-60-(60*0)+10 =

(add)

(0+50)-60-(0+10)=

(subtract)

(50-60-10)= (-10-10)= -20
by
heres step by step how to sovlie it 0+50x1-60-60x0+10

0+50-60-60x+10

0+50-60-0+10

50-60-0+10

50-60-10

-10-10

-20
by

The answer is 0. The order of operations dictates that the multiplication procedures must be done first. The order of operation is as follow:

roots and exponents
Then
multiplication and division
then
addition and subtraction. 

If there are more than one of each type of procedure, you do them from left to right, like we read in english. To solve the given problem, you must follow the order of operations to obtain the correct solution. 

0+50x1-60-60x0+10=

0+(50x1)-60-(60x0)+10=

0+(50)-60-(0)+10=

50-60-0+10=

(-10)-0+10=

(-10)+10= 0

by

The answer is 0

 

 
1st: scan thru to perform multiplications as they appear from left to right:
---
0+50-60-0+10
----
2nd: scan thru to perform additin and subtraction as they appear from left to 
righti
----
= 50-60+10
---
= 0
=============
Cheers,
Stan H.
============
by

The answer is 0 

 

The answer is 0
 
 
1st: scan thru to perform multiplications as they appear from left to right:
---
0+50-60-0+10
----
2nd: scan thru to perform additin and subtraction as they appear from left to 
righti
----
= 50-60+10
by

0+(50x1)-60-(60x0)+10=0

0+(50)-60-(0)+10=0

0+50-60-0+10=0

50-60-0+10=0

-10-0+10=0

-10+10=0

0 is  the final answer

by
You solve from left to right so I saw the zero, so anything to the left of the zero didn't matter any number times zero would be zero. So the answer is 10
by
I first got -20 but then i redid my work and got 0... i was taught PEMDAS but the addition and subtraction could go in either order... i did addition first and got -20 but then i did subtraction and got 0
by
PEMDAS. No parentheses and no exponents leaves us with multiplication, division, addition, and subtraction.  Multiplication and division are equal in status as are addition and subtraction.  They should be worked in order of appearance with multiplication and division being solved first.

0+50*1-60-60*0+10  Original problem

0+(50*1)-60-(60*0)+10  multiplication is sequestered for ease of solving

0+50-60-0+10  since 60*0=0 the - sign is irrevalent.

50-60+10=0  you can remove the 0s as they have no value.
by
i got -20 how is this wrong if you do pemdas in order? can someone explain?

0+50*1-60-60*0+10

no parenthesis or exponents so first multiplication leaves 0+50-60-0+10 /
then division:none / addition leaves 50-60-10 / subtraction leaves -20

calculator says zero though so im confused

anybody?
by

 

 

0+50=50

50 x 1=50

50 minus -60 leaves -10. 

-10 Then add another minus -60 is a -70.

-70 plus +10 Leaves -60

by
0+50x1-60-60x0+10= 50-60+10=0
by
0+50= 50
50x1= 50
50-60= -10
-10 - -60 = -70
-70x0= 0
0+10=10

the fact that the last x = 0
no mater what the sum is something x 0 is always = 0
So the true question is 0+10=10
by

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