how many liters of water will a trough whose cross section is an isosceles right triangle

continuation of the question is : that is 90 cm long and 50 cm wide at the top?if you could provide a drawing. and how do you solve or what formula will be used to know how many liters does it contain when the depth of the water is 15 cm? thank you
in Geometry Answers by Level 1 User (120 points)

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1 Answer

step 1: get area av isos triangel with base=50 cm . . . angels=60 deg, hite= side*kosine(60 deg) or yukan yuze herons formuls . . . base=50, hite=43.30127, area=1082.53175 . . . step 2...Volume=leng*area=90*1082.53175=97427.8575 cc . . . step 3...liter=1000 cc, so volume=97.4278575 liters . . . or bout 97 liters
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