Y=5x-7 -3x-2y=-12
how do you solve equation by substitution?
y=5x-7,
-3x-2y=-12
place the y value 5x-7 into the equation in substitution of y and solve for x
-3x-2(5x-7) = -12
-3x-10x+14 =-12
-13x=-26
26=13x
26/13=x
2=x
now place the found value of x back into either original given equation
Y=5x-7 or -3x-2y=-12
y=5(2)-7 or -3(2)-2y =-12
y=10-7 or -2y=-12+6
y=3 or y= -6/2 =3