<ABD and <BDE are supplementary. m<ABD=5X°,m<BDE=(17-18)°

Find both measures of both angles.
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1 Answer

Do you mean m<ABD=5X°, m<BDE=(17X-18)°?

If so, ABD+BDE=180°, so 5X+17X-18=180, 22X=198, X=198/22=9°.

So m<ABD=45°, m<BDE=(153-18)°=(180-45)°=135°.
by Top Rated User (1.1m points)

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