7/8 (9/10 divided by 5/8) =???? leave as as improper fraction. Need help

Question

Hey. I need some help in algebra ii. I'm having difficulties trying to understand and figure everything out. So if you may, please help me with the following. Thank you.

1. Perform the indicated operation. Leave the answer as an improper fraction: 7/8 (9/10 divided by 5/8) = __/__

2. Perform the indicated operation: 14a^2/10b^2 divided by 21a^2/15b^2

3. Perform the indicated operation: 7x^3/3 divided by 14x^2/6

4. Perform the indicated operation: a^2-2a+1/6 divided by (a^2-1)= ___/_____

Answer 1

1) 7/8 (9/10 divided by 5/8) =???? leave as as improper fraction. Need help

start in the parenthesis

to divide you switch the top and bottom of the second fraction and multiply

9/10 * 8/5 = 72/50  reduce this:

36/25

now multiply by 7/8

7/8 * 36/25 = 7/4 * 18/25 = 126/100 = 63/50

2). 14a^2/10b^2 divided by 21a^2/15b^2
again flip the second fraction

14a^2/10b^2 * 15b^2/21a^2

rewrite with common together

14a^2/21a^2 * 15b^2/10b^2 = 2/3 * 3/2 = 1

3). 7x^3/3 divided by 14x^2/6
7x^3/3 * 6/14x^3

rewrite

7x^3/14x^3 * 6/3 = 1/2 * 2/1 = 1

4). a^2-2a+1/6 divided by (a^2-1)

(a - 1)(a - 1)/6 * 1/(a - 1)(a + 1) = (a - 1) /6(a + 1)