x^(2)+y^(2)+2x+8y-8=0

Complete the square and write the equation of the circle in standard form.  Then determine the center and radius o the circle to graph the equation.
x^(2)+y^(2)+2x+8y-8=0

The equation in standard form is?
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1 Answer

x^2 +y^2 +2x +8y-8=0

(x+1)^2 +(y+4)^2-8 -17=0

(x+1)^2 +(y+4)^2 =5^2
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