application of calculus, minimum and maximum

Question

a man in a row boat 2miles fron the nearest point on a straight shore line wishes to reach a point 6miles further down the shore. If he can row at a rate of 3miles/hr, and run at a rate of 5miles/hr. How should he proceed in order to arrive at his destination in the shortest time. (pls I need d explanation of the solution as well)

Answer 1

???????????????? "arrive at his destinashun" ??????????????

him wanna GET THEER

Yu hav a rite trinagel, hite=2 miles=water

base=6 miles=on land

water speed=3, land speed=5

1. wae him mite go...along 2 miles, then 6 miles...

time=(2/3)+(6/5)=1.2+0.666666666...=1.8666666...ours

2. dif wae...go bi see...distans=diagonal av triangel=sqrt(36+4)=sqrt(40)=6.32455532 mile

time=6.324555/3=2.108185 ours

3. Jenral...him kood go strate line tuward sum point on land tween 2 points

Thats yer job