C=10x + 20y

x>0, y>0

3x+5y>30
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1 Answer

1) x>0,y>0 represents first quadrant Q1.

2) draw the line 3x +5y = 30.

 

x  0  10
y 6 0
(x ,y )   (0,6) (10,0)

3)plot the points and join them draw the line.

This line intersects x-axis  at (10,0)

and  y-intersects  y- axis at (0,6)

point c =10x+20y value
(0 ,0) c = 10*0+20*0 0
(10, 0 ) c= 10*10+20*0 100
(0 ,6) c= 10*0 +20*6 120

minimum value is 100 at the point (10,0)

by Level 4 User (5.5k points)

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