x=200x/(6.253-158)+20
in Algebra 2 Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

x = 200x/(6.253x - 158) + 20 subtract 20 from both sides

x - 20 = 200x/(6.253x - 158)

(x - 20)(6.253x - 158) = 200x

6.253x^2 - 158x - 125.06x + 3160 = 200x

6.253x^2 - 283.06x + 3160 - 200x = 0

6.253x^2 - 483.06x + 3160 = 0

qudratic equation time!

[-b +or- sqrt(b^2 - 4ac)] / 2a,

a = 6.253, b = - 483.06, c = 3160

[483.06 +or- sqrt((-483.06)^2 - 4 * 6.253 * 3160)]/2*6.253

[483.06 +or- sqrt(233346.9636 - 79037.92)]/ 12.506

[483.06 +or- sqrt(154309.0436)] /12.506

 

by Level 10 User (55.7k points)

Related questions

1 answer
0 answers
asked Mar 2, 2013 in Calculus Answers by anonymous | 441 views
1 answer
asked Jun 27, 2012 in Algebra 1 Answers by genia Level 1 User (120 points) | 1.3k views
1 answer
asked Sep 19, 2013 in Geometry Answers by Math | 544 views
1 answer
1 answer
asked Feb 22, 2013 in Word Problem Answers by anonymous | 464 views
2 answers
asked Jan 14, 2013 in Calculus Answers by anonymous | 674 views
2 answers
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
87,542 questions
99,768 answers
2,417 comments
504,742 users