I nid quick help please
in Algebra 2 Answers by Level 1 User (120 points)

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Question: 1 of 3 terms of GP is -24, if their sum is -56/3 and their product is 512, find the other 2.

Let the three terms of the GP be: a, ar and ar^2, where r is the common ratio.

Sum is -56/3, i,.e. a(1 + r + r^2) = -56/3

Product is 512, i.e. a*ar*ar^2 = 512

i.e. (ar)^3 = 512 = 8^3

or, ar = 8

We are told, 1 of 3 terms is -24, i.e.

a = -24  implies r = -1/3 (since ar = 8)

or,

ar = -24  (this option not valid since we are given that ar = 8)

or,

ar^2 = -24  implies r = -3 since ar = 8

but ar^2 = -24 with r = -3 implies a = -24/9 = -8/3

and ar = 8 with r = -3 implies a = -8/3

This leaves us with the 1st option, a = -24 with r = -1/3 and the 3rd option, a = -8/3 with r = -3

Check

The three elements are: -24, 8, - 8/3,  OR  -8/3, 8, -24   (i.e. a, ar, ar^2)

It should be noted that both options give the same three elements, just in different orders.

Sum = -24 + 8 - 8/3 = -16 - 8/3 = -48/3 - 8/3 = -56/3 -- check

Product = (-24)*(8)*(-8/3) = (-8)*(8)*(-8) = 512 -- check

Answer: The three elements are: -24, 8, -8/3

by Level 11 User (81.5k points)
edited by
Thanks a lot. I was getting confused on how to use -24
Sorry, I had  a sign error in my working.
I had r = 3, instead of r = -3, for the third option.
This actually makes no difference to the final answer, but gives two different GPs, with common elements, albeit in different orders of progression.

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