solve (x+3)/3+ (x+3)/x=2, in simplest a+bi form?

Question

Sove for x and express the answer in simplest a+bi form? please

Answer 1

(x + 3)/3 + ( x+ 3)/x = 2          * 3x

3x(x+3)/3 + 3x(x+3)/x = 2*3x

x^2 + 3x + 3x + 9  = 6x

x^2 + 6x + 9 = 0

x^2 + 9 = 0

x^2 = - 9

x = sgrt ( - 9) and          x = - sqrt( - 9)

x = sqrt ( - 1*9) AND    x = - sqrt(-1*9)
  
x = 3(i)    and         x = - 3(i)                            - = sqrt( - 1)

Answer 2

(x + 3) / 3 + (x + 3) / x = 2, where x =/= 0
x(x + 3) / 3x + 3(x + 3) / 3x = 2
(x^2 + 3x) / 3x + (3x + 9) / 3x = 2
(x^2 + 3x + 3x + 9) / 3x = 2
(x^2 + 6x + 9) / 3x = 2
(x^2 + 6x + 9) = 6x
x^2 + 6x + 9 = 6x
x^2 + 6x - 6x + 9 = 0
x^2 + 9 = 0
x^2 = -9
x = sqrt(-9) or = -sqrt(-9)
x = 3sqrt(-1) or =-3sqrt(-1)
x = 3i or = -3i