Please Help. I need to solve using Lagrange Multiplier's.

The atmospheric re-entry temperature on the surface of a space capsule represented by the ellipsoid 4x^2 + y^2 + 4z^2 = 16 is given by T = 8x^2 + 4yz −16z + 600    (°C ) .

The material from which the capsule is made can only withstand a temperature of 650°C. Will the occupants of the space-craft survive re-entry?

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The atmospheric re-entry temperature on the surface of a space capsule represented by the ellipsoid 4x^2 + y^2 + 4z^2 = 16 is given by T = 8x^2 + 4yz −16z + 600    (°C ) .

The material from which the capsule is made can only withstand a temperature of 650°C. Will the occupants of the space-craft survive re-entry?

The temperature is: T(x,y,z) = 8x^2 + 4yz – 16z + 600

The constraint is: f(x,y,z) = 4x^2 + y^2 + 4z^2 – 16 = 0

We wish to maximise the temperature T() subject to the constraint f().

The Langrangian is: L(x,y,z,λ) = T(x,y,z) – λ.f(x,y,z)

Taking the partial differentials,

Tx = λ.fx; 16x = λ.8x à λ = 2

Ty = λ.fy; 4x = λ.2y à 2z = λy à 2z = 2y à y = z

Tz = λ.fz; 4y – 16 = λ.8z à y – 4 = 2λz à y – 4 = 4y à y = -4/3, z = -4/3

f = 0; 4x^2 + y^2 + 4z^2 – 16 = 0

              4x^2 + 5(-4/3)^2 = 16

              4x^2 + 80/9 = 16

              x^2 + 20/9 = 4

x^2 = (36 – 20)/9 = 16/9

x = ± 4/3

Max temp occurs at the positions (x,y,z) = (-4/3, -4/3, -4/3), (4/3, -4/3, -4/3)

Value of this max temp is: 8x^2 + 4yz – 16z + 600 = 8(4/3)^2 + 4(4/3)^2 – 16(4/3) + 600

Tmax = 12(16/9) – 64/3 + 600 = 600 ⁰C

Since Tmax is less than 650 ⁰C, then the astronauts will survive re-entry

by Level 11 User (81.5k points)

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