how ro solve this?lim x=0,sin kx/x

i cant make it ..and do it work
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1 Answer

mi ges....that stuf shood be

sine(kx) / x

& yu want limit as x gotu 0

yuze power seerees...sine(x)=x -x^3/3!+-...

yu hav sine(kx)=kx-(kx)^3/3!+-...

as x gotu 0, sine(kx) gotu kx, so sine(kx)/x gotu k
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