lim[x:0,sin(2x)cos(4x)/tan(3x)]

find the limit and show the steps. the answer should be 0
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1 Answer

lim(x->0) [sin(2x)cos(4x)] / tan (3x)
= lim(x->0) [(2cos(2x))(-4sin(4x))] / 3sec^2 (3x) [By L hospital rule]
= [(2cos(0)(-4sin(0)] / 3sec^2 (0)
= [(2)(0)] / 3
= 0 / 3
= 0
by

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