Limx tends to infinity (x-sinx/x+cos^2x)^1/2

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Given lim x->infinity((x-sinx)/(x+cos^2x))^(1/2)

By squeeze theorem

lim x->infinity((x-sinx)/(x+cos^2x))^(1/2)=1

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by Level 8 User (30.1k points)

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