How to solve this problem to the limit x tends to zero ?

Question

(X+3)^2 - 9 ÷ X

Answer 1

me assume that stuf shood be... (x+3)^2 -(9/x)... as x gotu 0, -9/x blo up downward...it gotu - infility... x+3 dont matter...same as 0, kompared tu infinity

Answer 2

[(x+3)^2 - 9]/x

[x^2 + 2x + 9 - 9]/x

[x^2 + 2x]/x

x + 2

The function reduces to (x + 2) and the limit of this as x tends to zero is 2