I need to know how to solve an triple ordered solution as seen above.
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1 Answer

x + y + z = 8

2x + 5y + 2z = 25

-x + 6y - 3z = 7

add the first to the third

x + y + z = 8

2x + 5y + 2z = 25

0x + 7y - 2z = 15

multiply the first by -2 on both sides

-2x - 2y - 2z = -16

2x + 5y + 2z = 25

0x + 7y - 2z = 15

add the second to the first

0x + 3y + 0z = 9

2x + 5y + 2z = 25

0x + 7y - 2z = 25

divide the first by 3 on both sides

0x + y + 0z = 3

2x + 5y + 2z = 25

0x + 7y - 2z = 25

Now we know y = 3

multiply the first by -7 on both sides

0x - 7y + 0z = -21

2x + 5y + 2z = 25

0x + 7y - 2z = 25

add the first to the third

0x - 7y + 0z = -21

2x + 5y + 2z = 25

0x + 0y - 2z = 4

divide the third by -2

0x - 7y + 0z = -21

2x + 5y + 2z = 25

0x + 0y + z = -2

No we know z = -2

divide the first by -7

0x + y + 0z = 3

2x + 5y + 2z = 25

0x + 0y + z = -2

multiply the first by -5 and the third by -2

0x - 5y + 0z = -15

2x + 5y + 2z = 25

0x + 0y - 2z = 4

add the first and third to the second

0x - 5y + 0z = -15

2x + 0y + 0z = 14

0x + 0y - 2z = 4

divide the second by 2

0x - 5y + 0z = -15

x + 0y + 0z = 7

0x + 0y - 2z = 4

Now we know x = 7

Answer:  (7, 3, -2)
by Level 13 User (103k points)

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