Help me solve this problem
The length of a rectangle exceeds three times the
width by 6 feet, and the perimeter is 188 feet. Find
the dimensions of the rectangle
2l + 2w = 188
l = 3w + 6
2(3w + 6) + 2w = 188
6w + 12 + 2w = 188
8w = 176
w = 22
l = 3w + 6
l = 3(22) + 6
l = 72
2l + 2w = 188
2(72) + 2(22) = 188
144 + 44 = 188
188 = 188
The length is 72 feet, the width is 22 feet