Question

Use the equation to answer the following questions. y = -3x^2 + 3x + 6
1. What form is the equation in? ______________________________________
2. Which way does the graph open? ____________________________________
3. Change the equation to vertex form: ________________________________
Work:
4. List the transformations (Please use the correct terminology.): _________________________________
_______________________________________________________________________________________
5. What are the x-intercepts? (List as points)____________________________________________________
6. What is the y-intercept? (Also a point) _____________________
7. What is the Axis of Symmetry (Remember this is an equation!) ____________________________________
8. Write the equation in the only form left

Answer 1

y=-3x^2+3x+6

1...form???? maebee teech want "standard form" ?????

2...wae tu go???...down

3... vertex....y=-3*(x^2-x-2)...=-3*(x-0.5)^2-2.25...(y+3)+2.25=(x-0.5)^2...y+5.25=(x-0.5)^2

4...????????

5. "x-intersept"...thats guvt-krat gibberish for points weer y=0 (if NE)

...so -(y/3)=x^2-x-2...yuze quadratik equashun tu get zeroes...x=1.618033989 & x=-0.618033989

6..."y-intersept"...thats weer guvt krats sae x=0...so y=-3*(-2)...+6

7..."axis av symmetry"...vertikal line thru x=+0.5

8..."oenlee form left" ????????????????