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−3+log5(2x)=−1

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−3+log5(2x)=−1

−3+log5(2x)=−1

solving equations

asked May 11, 2015 in Calculus Answers by anonymous

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2 Answers

log5(2x)-3=-1

log5(2x)=2

5^[log5(2x)]=5^2

2x=5^2=25

x=25/2=12.5

answered May 11, 2015 by muneepenee

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Given −3+log_5(2x)=−1
log_5(2x)=-1+3
log_5(2x)=2
log x = log (25/2)
x= 25/2

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answered May 13, 2015 by John Marsh Level 8 User (30.1k points)

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