The velocity of a particle moving along a vertical lone is given by the equation v(t)=((1t/3)-1)^2. The particles position at time zero is 4.

Question

Do whichever ones you can. Thanks. A) At what time(s) is the particle moving upward? B) For what value(s) of t does the particle's speed equal the particle's velocity? C) Find the total distance traveled by the particle from t=3 to t=9

Answer 1

?????????????????? "velosity" ????????????? maebee yu meen

SPEED

?????????????? "LONE" ???? yu borro munee from a banker ??????

maebee the vertikal speed=(t/3)-1, so speed=0 at t=3

after that, speed > 0

??????? 3 sekonds ????????

speed ALWAES = absolute value(velosity)

Answer 2

A) The particle is moving upward or stationary; it never moves down because of the square, which is always >0. When t=3 v=0, so the particle is stationary. At all other times it is moving up.

B) Speed is the magnitude of velocity, but since v(t)>0 always the speed is equal to the velocity because it's always positive or zero.

C) distance=vt=t((t/3)-1)^2=0 at t=3 and 9*4=36 when t=9, and the starting distance is 4, making the total distance 36+4=40.