determine the first derivative (dx/dy) of :y = (tan 3x)^2

determine the first derivative (dx/dy) of :y = (tan 3x)^2
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dy/dx=(2tan(3x))(3sec^2(3x)). dx/dy=1/(dy/dx)=1/(2tan(3x))(3sec^2(3x))=6cot(3x)cos^2(3x);

dx/dy=cos^3(3x)/sin(3x) or cos^3(3x)cosec(3x).
by Top Rated User (1.1m points)

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