For any set A,B,C in a universal set U, (A/B)C = A/(BC).....State true or false and give a proof supporting your answer.
in Algebra 2 Answers by Level 2 User (1.3k points)

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

False, because if, for example, A=2, B=3, C=4, then A/B=2/3 and (A/B)C=(2/3)*4=8/3; but BC=3*4=12 and A/(BC)=2/12=1/6. The numbers 2, 3, 4, in N, are part of U, because N is a subset of U so (A/B)C = A/(BC) cannot be universally true.

by Top Rated User (1.1m points)
But according to question.... A B & C are subsets of U.... So does your explanation implies...??

Sorry, I assumed they were elements rather than sets. However, a set can consist of one element or, as I thought, A, B and C were individual elements of the U set, forming a set { A B C ... } rather than sets of elements within U. The question then arises; if these are sets what is the meaning of division or multiplication in the context? How do you multiply and divide sets of more than one element? The key thing, I think, is that C is moved from numerator to denominator position, so whatever the meaning, C is in a different arithmetic position, which would make the statement false in any case. If you take my answer to be a special case of a 1-element set, the statement is false, and to be true it must apply to all sets, including 1-element sets. I hope I haven't confused you!

Well you did a little but I'm going to take my chances.... Thank you for your help and it would be great if you could explain about it more but it's fine as well if you don't want to coz I have a book for that.... Hence, I'm going to assume these sets are singleton and apply your main answer....

Sorry for any confusion and for the delay in replying (it took me a while to find your comment!). What struck me about your question was division and multiplication: (A/B)C and A/(BC) I took to be the normal arithmetic application of division and multiplication, which applies to numbers rather than sets (at least, in my limited experience with sets); that's why I assumed A, B and C were just numbers, single elements within U. So my line of thought was that (A/B)C expands to AC/B, with C in the numerator formed by the product of A and C; while A/(BC) contains the product of B and C in the denominator, so the two expressions are different.

Since it's over 50 years since I studied mathematics you are probably more familiar with sets than I am, and perhaps it's possible to apply multiplication and division to whole sets (as in matrices, for example); but I personally don't know how it's done.

I would be interested to know if you had a different interpretation. Yes, I will willingly offer explanations you need, as long as I understand the subject. You only have to ask.

Thank you very much on your support.... And I'll inform you as soon as I find an alternative answer or the same

Related questions

1 answer
asked Feb 16, 2016 in Algebra 2 Answers by karan91 Level 2 User (1.3k points) | 477 views
1 answer
2 answers
asked Feb 17, 2016 in Algebra 2 Answers by karan91 Level 2 User (1.3k points) | 655 views
1 answer
1 answer
1 answer
1 answer
1 answer
asked Feb 24, 2016 in Algebra 2 Answers by karan91 Level 2 User (1.3k points) | 527 views
2 answers
1 answer
2 answers
asked Feb 22, 2016 in Algebra 2 Answers by karan91 Level 2 User (1.3k points) | 656 views
1 answer
asked Feb 22, 2016 in Algebra 2 Answers by karan91 Level 2 User (1.3k points) | 914 views
1 answer
1 answer
1 answer
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
87,544 questions
99,727 answers
2,417 comments
479,654 users